\(\frac{7 \cdot 2}{15 \cdot 2} + \frac{3 \cdot 3}{10 \cdot 3} = \frac{14}{30} + \frac{9}{30} = \frac{14+9}{30} = \frac{23}{30}\)\(\frac{7 \cdot 2}{15 \cdot 2} - \frac{3 \cdot 3}{10 \cdot 3} = \frac{14}{30} - \frac{9}{30} = \frac{14-9}{30} = \frac{5}{30} = \frac{1}{6}\)\(\frac{5}{12} \cdot \frac{9}{20} = \frac{5 \cdot 9}{12 \cdot 20} = \frac{1 \cdot 3}{4 \cdot 4} = \frac{3}{16}\)13 + \frac{1}{40} = 13\frac{1}{40}16\frac{19}{40} - 13\frac{1}{40} = (16-13) + (\frac{19}{40} - \frac{1}{40}) = 3 + \frac{18}{40} = 3 + \frac{9}{20} = 3\frac{9}{20}Ответ: а) \(\frac{23}{30}\); б) \(\frac{1}{6}\); г) \(\frac{3}{16}\); е) \(3\frac{9}{20}\).