5. Решите уравнения: 1) \(8\frac9{10}-x=4\frac56\); 2) \(\frac9{14}+(x-\frac37)=\frac{23}{28}\).

1. \(8\frac9{10}-x=4\frac56\).
   \(x=8\frac9{10}-4\frac56=\frac{89}{10}-\frac{29}{6}=\frac{267}{30}-\frac{145}{30}=\frac{122}{30}=\frac{61}{15}=4\frac1{15}\).
2. \(\frac9{14}+(x-\frac37)=\frac{23}{28}\).
   \(x-\frac37=\frac{23}{28}-\frac9{14}=\frac{23}{28}-\frac{18}{28}=\frac5{28}\).
   \(x=\frac5{28}+\frac37=\frac5{28}+\frac{12}{28}=\frac{17}{28}\).

Ответ: 1) \(x=4\frac1{15}\); 2) \(x=\frac{17}{28}\).