Ответ:

  1. \(3\sqrt{8}-\sqrt{50}+2\sqrt{18}=3\cdot2\sqrt{2}-5\sqrt{2}+2\cdot3\sqrt{2}=(6-5+6)\sqrt{2}=7\sqrt{2}\).
  2. \(\sqrt{75}-0,1\sqrt{300}-\sqrt{27}=5\sqrt{3}-0,1\cdot10\sqrt{3}-3\sqrt{3}=(5-1-3)\sqrt{3}=\sqrt{3}\).

Ответ: 1) 7√2; 2) √3.