5.272. Представьте смешанные числа в виде неправильной дроби: a) 9 1/4; b) 5 6/7; c) 2 3/10; d) 8 12/17; e) 11 5/6

a) \(9\frac{1}{4} = \frac{9 \cdot 4 + 1}{4} = \frac{36 + 1}{4} = \frac{37}{4}\) b) \(5\frac{6}{7} = \frac{5 \cdot 7 + 6}{7} = \frac{35 + 6}{7} = \frac{41}{7}\) c) \(2\frac{3}{10} = \frac{2 \cdot 10 + 3}{10} = \frac{20 + 3}{10} = \frac{23}{10}\) d) \(8\frac{12}{17} = \frac{8 \cdot 17 + 12}{17} = \frac{136 + 12}{17} = \frac{148}{17}\) e) \(11\frac{5}{6} = \frac{11 \cdot 6 + 5}{6} = \frac{66 + 5}{6} = \frac{71}{6}\)