Ответ:
\(\sin\alpha=\sqrt{1-\cos^2\alpha}=\sqrt{1-\frac{9}{16}}=\sqrt{\frac{7}{16}}=\frac{\sqrt7}{4}\).
Javob: \(\frac{\sqrt7}{4}\) (C).
\(\sin\alpha=\sqrt{1-\cos^2\alpha}=\sqrt{1-\frac{9}{16}}=\sqrt{\frac{7}{16}}=\frac{\sqrt7}{4}\).
Javob: \(\frac{\sqrt7}{4}\) (C).