Ответ:
Ikki burchak formulasi: \(\sin2\alpha=2\sin\alpha\cos\alpha\).
\(\sin2\alpha=2\cdot\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=1\).
Javob: 1 (B).
Ikki burchak formulasi: \(\sin2\alpha=2\sin\alpha\cos\alpha\).
\(\sin2\alpha=2\cdot\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=1\).
Javob: 1 (B).