61. Agar sinα=1/2, cosα=√3/2 bo‘lsa, sin2α ni hisoblang.

\(\sin2\alpha=2\sin\alpha\cos\alpha=2\cdot\frac12\cdot\frac{\sqrt3}{2}=\frac{\sqrt3}{2}\).

Javob: \(\frac{\sqrt3}{2}\) (A).