Ответ:\(64^{1/2}=\sqrt{64}=8\).\(27^{1/3}=\sqrt[3]{27}=3\).\(8^{2/3}=(\sqrt[3]{8})^2=2^2=4\).\(81^{3/4}=(\sqrt[4]{81})^3=3^3=27\).\((8^{1/12})^{-4}=8^{-1/3}=\dfrac{1}{\sqrt[3]{8}}=\dfrac12\).