Ответ:Период \(T = \frac{10}{10} = 1\,\text{с}\), \(T = 2\pi\sqrt{\frac{m}{k}}\), \(1 = 2\pi\sqrt{\frac{m}{36}}\), \(\frac{1}{4\pi^2} = \frac{m}{36}\), \(m = \frac{36}{4\pi^2} \approx 0.91\,\text{кг}\). Ответ: \(m \approx 0.91\,\text{кг}\).