Решение:
\( \frac{10 \cdot 5}{7^2 - 25} - \frac{10 · 5}{7 + 5} \)
\( 7^2 - 25 = 49 - 25 = 24 \)
\( 7 + 5 = 12 \)
\( \frac{50}{24} - \frac{50}{12} \)
\( \frac{50}{24} - \frac{50 · 2}{12 · 2} = \frac{50}{24} - \frac{100}{24} \)
\( \frac{50 - 100}{24} = \frac{-50}{24} \)
\( \frac{-50}{24} = \frac{-25}{12} \)
\( -\frac{25}{12} = -2 \frac{1}{12} \)
Ответ: \( -\frac{25}{12} \) или \( -2 \frac{1}{12} \)