Ответ:

Решение:

a) \( \frac{5}{48} + \frac{3}{8} + \frac{1}{48} \)

\[ (\frac{5}{48} + \frac{1}{48}) + \frac{3}{8} = \frac{6}{48} + \frac{3}{8} = \frac{1}{8} + \frac{3}{8} = \frac{4}{8} = \frac{1}{2} \]

б) \( (\frac{7}{15} + \frac{2}{9}) - \frac{2}{15} \)

\[ (\frac{7}{15} - \frac{2}{15}) + \frac{2}{9} = \frac{5}{15} + \frac{2}{9} = \frac{1}{3} + \frac{2}{9} = \frac{3}{9} + \frac{2}{9} = \frac{5}{9} \]

в) \( \frac{14}{27} - (\frac{5}{27} + \frac{1}{6}) \)

\[ \frac{14}{27} - \frac{5}{27} - \frac{1}{6} = \frac{9}{27} - \frac{1}{6} = \frac{1}{3} - \frac{1}{6} = \frac{2}{6} - \frac{1}{6} = \frac{1}{6} \]

Ответ: а) \( \frac{1}{2} \); б) \( \frac{5}{9} \); в) \( \frac{1}{6} \).