Ответ:
- \((\sqrt{12}+\sqrt{27})\sqrt3=(2\sqrt3+3\sqrt3)\sqrt3=5\cdot3=15\).
- \((\sqrt8-\sqrt{72})\sqrt2=(2\sqrt2-6\sqrt2)\sqrt2=-4\cdot2=-8\).
- \(3\sqrt5+(\sqrt{75}-\sqrt{15})\sqrt3=3\sqrt5+(5\sqrt3-\sqrt{15})\sqrt3=3\sqrt5+15-3\sqrt5=15\).
- \((\sqrt{60}-\sqrt{45})\sqrt5-10\sqrt3=(2\sqrt{15}-3\sqrt5)\sqrt5-10\sqrt3=10\sqrt3-15-10\sqrt3=-15\).
- \((\sqrt{200}+5\sqrt{20})\sqrt5-\sqrt{1000}=(10\sqrt2+10\sqrt5)\sqrt5-10\sqrt{10}=10\sqrt{10}+50-10\sqrt{10}=50\).
- \((\sqrt{300}-6\sqrt{50})\sqrt2-\sqrt{600}=(10\sqrt3-30\sqrt2)\sqrt2-10\sqrt6=20\sqrt6-60-10\sqrt6=10\sqrt6-60\).
Ответ: 1) 15; 2) −8; 3) 15; 4) −15; 5) 50; 6) \(10\sqrt6-60\).
