15.13. а) $$ a_n = \frac{1}{n+5} $$
- n = 1; $$ a_1 = \frac{1}{1+5} = \frac{1}{6} $$
- n = 2; $$ a_2 = \frac{1}{2+5} = \frac{1}{7} $$
- n = 3; $$ a_3 = \frac{1}{3+5} = \frac{1}{8} $$
- n = 4; $$ a_4 = \frac{1}{4+5} = \frac{1}{9} $$
- n = 5; $$ a_5 = \frac{1}{5+5} = \frac{1}{10} $$
Ответ: $$\frac{1}{6}; \frac{1}{7}; \frac{1}{8}; \frac{1}{9}; \frac{1}{10} $$.