-3 г) ап = 4п-1

Г) $$ a_n = \frac{-3}{4n - 1} $$

1. n = 1; $$ a_1 = \frac{-3}{4 \times 1 - 1} = \frac{-3}{3} = -1 $$


2. n = 2; $$ a_2 = \frac{-3}{4 \times 2 - 1} = \frac{-3}{7} $$


3. n = 3; $$ a_3 = \frac{-3}{4 \times 3 - 1} = \frac{-3}{11} $$


4. n = 4; $$ a_4 = \frac{-3}{4 \times 4 - 1} = \frac{-3}{15} = -\frac{1}{5} $$


5. n = 5; $$ a_5 = \frac{-3}{4 \times 5 - 1} = \frac{-3}{19} $$

Ответ: $$ -1; -\frac{3}{7}; -\frac{3}{11}; -\frac{1}{5}; -\frac{3}{19} $$.