4) -3a4b32 -2m²3. 8m³ 3a3b2

4) $$\left(-\frac{3a^4b^3}{8m^5}\right)^2 \cdot \left(-\frac{2m^2}{3a^3b^2}\right)^3 = \frac{(3a^4b^3)^2}{(8m^5)^2} \cdot \left(-\frac{(2m^2)^3}{(3a^3b^2)^3}\right) = \frac{9a^8b^6}{64m^{10}} \cdot \left(-\frac{8m^6}{27a^9b^6}\right) = -\frac{9a^8b^6 \cdot 8m^6}{64m^{10} \cdot 27a^9b^6} = -\frac{a^8b^6m^6}{8m^{10} \cdot 3a^9b^6} = -\frac{1}{24am^4}$$

Ответ: $$- \frac{1}{24am^4}$$