2) mn³; 24p (- 6p; mn)

2) $$\frac{mn^3}{24p} \cdot (-\frac{6p}{m^2n}) = - \frac{mn^3 \cdot 6p}{24p \cdot m^2n} = - \frac{6mn^3p}{24m^2np} = - \frac{n^2}{4m}$$

Ответ: $$- \frac{n^2}{4m}$$