B) $$^3\sqrt{-2a^2b^4\sqrt[5]{5a^3}}$$;

B) $$^3\sqrt{-2a^2b^4\sqrt[5]{5a^3}}$$;

$$^3\sqrt{-2a^2b^4\sqrt[5]{5a^3}} = \sqrt[3]{-2a^2b^4\sqrt[5]{5a^3}} = \sqrt[3]{-2a^2b^4(5a^3)^{\frac{1}{5}}} = \sqrt[3]{-2a^2b^4\cdot 5^{\frac{1}{5}}a^{\frac{3}{5}}} = (-2b^4)^{\frac{1}{3}}a^{\frac{2}{3}}5^{\frac{1}{15}}a^{\frac{1}{5}} = (-2b^4)^{\frac{1}{3}}a^{\frac{2}{3} + \frac{1}{5}}5^{\frac{1}{15}} = (-2b^4)^{\frac{1}{3}}a^{\frac{10 + 3}{15}}5^{\frac{1}{15}} = (-2b^4)^{\frac{1}{3}}a^{\frac{13}{15}}5^{\frac{1}{15}} = \sqrt[3]{-2b^4} \cdot \sqrt[15]{a^{13}} \cdot \sqrt[15]{5}$$

Ответ: $$\sqrt[3]{-2b^4} \cdot \sqrt[15]{a^{13}} \cdot \sqrt[15]{5}$$