5c-3c² a-b³ b-a c

$$ \frac{(a-b)^3}{b-a} = \frac{-(b-a)^3}{b-a} = -(b-a)^2 $$

$$ \frac{5c-3c^2}{c} = \frac{c(5-3c)}{c} = 5-3c $$

Ответ: $$ -(b-a)^2 $$, $$ 5-3c $$