д) (5с - 1)(-4) + (3c - 9)·(-3); e) -1,5 (-4b + 8) - (10 + b); ж)-8.(1-1)+6.(1-10): 5 4 3 3) 7. (x - 1,8) - 4. (x - 1,3). 7 4

Упростите выражение:

1. д) \[(5c - 1)(-4) + (3c - 9) \cdot (-3) = -20c + 4 - 9c + 27 = (-20c - 9c) + (4 + 27) = -29c + 31\]
2. e) \[-1.5 \cdot (-4b + 8) - (10 + b) = 6b - 12 - 10 - b = (6b - b) + (-12 - 10) = 5b - 22\]
3. ж) \[-8 \cdot (\frac{1}{4}a - \frac{1}{8}) + 6 \cdot (\frac{1}{3}a - \frac{1}{16}) = -2a + 1 + 2a - \frac{3}{8} = (-2a + 2a) + (1 - \frac{3}{8}) = 0 + \frac{5}{8} = \frac{5}{8}\]
4. з) \[7 \cdot (\frac{5}{7}x - 1.8) - 4 \cdot (\frac{3}{4}x - 1.3) = 5x - 12.6 - 3x + 5.2 = (5x - 3x) + (-12.6 + 5.2) = 2x - 7.4\]

Ответ: д) -29c + 31; e) 5b - 22; ж) \(\frac{5}{8}\); з) 2x - 7.4