Hisoblang: (1 - 1/2) * (1 - 1/3) * (1 - 1/4) * ... * (1 - 1/50)

Let's simplify each term in the product:

\[ (1 - \frac{1}{2}) = \frac{2-1}{2} = \frac{1}{2} \]

\[ (1 - \frac{1}{3}) = \frac{3-1}{3} = \frac{2}{3} \]

\[ (1 - \frac{1}{4}) = \frac{4-1}{4} = \frac{3}{4} \]

We can see a pattern emerging. The general term is \( (1 - \frac{1}{n}) = \frac{n-1}{n} \).

So, the product can be written as:

\[ \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} \times \dots \times \frac{50-1}{50} \]

\[ \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} \times \dots \times \frac{49}{50} \]

This is a telescoping product. Many terms will cancel out:

\[ \frac{\cancel{1}}{\cancel{2}} \times \frac{\cancel{2}}{\cancel{3}} \times \frac{\cancel{3}}{\cancel{4}} \times \dots \times \frac{\cancel{49}}{50} \]

After cancellation, we are left with:

\[ \frac{1}{50} \]

Ответ: 1/50