We need to convert the repeating decimals to fractions and then add them.
Let \( x = 0.(6) \). Then \( 10x = 6.(6) \). Subtracting the first equation from the second:
\[ 10x - x = 6.(6) - 0.(6) \]
\[ 9x = 6 \]
\[ x = \frac{6}{9} = \frac{2}{3} \]
Let \( y = 0.(2) \). Then \( 10y = 2.(2) \). Subtracting the first equation from the second:
\[ 10y - y = 2.(2) - 0.(2) \]
\[ 9y = 2 \]
\[ y = \frac{2}{9} \]
Now, we add the fractions:
\[ 0.(6) + 0.(2) = \frac{2}{3} + \frac{2}{9} \]
To add these, we find a common denominator, which is 9:
\[ \frac{2 \cdot 3}{3 \cdot 3} + \frac{2}{9} = \frac{6}{9} + \frac{2}{9} = \frac{6+2}{9} = \frac{8}{9} \]
The result as a simple fraction is 8/9.
Ответ: 8/9