Вопрос:

Yettita ketma-ket natural sonning yig'indisi 133 ga teng. Eng kichik sonni toping.

Ответ:

Let the smallest natural number be 'x'.

Since the numbers are consecutive natural numbers, the seven consecutive numbers are:

\[ x, x+1, x+2, x+3, x+4, x+5, x+6 \]

The sum of these seven numbers is given as 133.

\[ x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) = 133 \]

Combine the 'x' terms and the constant terms:

\[ 7x + (1+2+3+4+5+6) = 133 \]

Calculate the sum of the constants:

\[ 1+2+3+4+5+6 = 21 \]

So the equation becomes:

\[ 7x + 21 = 133 \]

Now, solve for 'x':

Subtract 21 from both sides:

\[ 7x = 133 - 21 \]

\[ 7x = 112 \]

Divide by 7:

\[ x = \frac{112}{7} \]

\[ x = 16 \]

The smallest natural number is 16.

We can check this: The numbers are 16, 17, 18, 19, 20, 21, 22. Their sum is \( 16+17+18+19+20+21+22 = 133 \).

Ответ: 16

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