6) h(x)=sin 2x- r) h(x)=cos 3x+ 6) h(x) = √cos x; r) h(x) = tg.

б) h(x) = sin(2x - \(\frac{\pi}{3}\))

• Пусть f(x) = 2x - \(\frac{\pi}{3}\), g(x) = sin x. Тогда h(x) = g(f(x)) = sin(2x - \(\frac{\pi}{3}\)).

г) h(x) = cos(3x + \(\frac{\pi}{4}\))

• Пусть f(x) = 3x + \(\frac{\pi}{4}\), g(x) = cos x. Тогда h(x) = g(f(x)) = cos(3x + \(\frac{\pi}{4}\)).

б) h(x) = \(\sqrt{\cos x}\)

• Пусть f(x) = cos x, g(x) = \(\sqrt{x}\). Тогда h(x) = g(f(x)) = \(\sqrt{\cos x}\).

г) h(x) = tg \(\frac{1}{x}\)

• Пусть f(x) = \(\frac{1}{x}\), g(x) = tg x. Тогда h(x) = g(f(x)) = tg \(\frac{1}{x}\).