Краткое пояснение: Используем формулы суммы и разности кубов: \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\) и \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\).
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\(x^3 + y^3 = (x + y)(x^2 - xy + y^2)\)
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\(m^3 - n^3 = (m - n)(m^2 + mn + n^2)\)
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\(a^3 + 8 = a^3 + 2^3 = (a + 2)(a^2 - 2a + 4)\)
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\(b^3 - 27 = b^3 - 3^3 = (b - 3)(b^2 + 3b + 9)\)
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\(64 + c^3 = 4^3 + c^3 = (4 + c)(16 - 4c + c^2)\)
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\(125 - d^3 = 5^3 - d^3 = (5 - d)(25 + 5d + d^2)\)
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\(m^3 + 216 = m^3 + 6^3 = (m + 6)(m^2 - 6m + 36)\)
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\(343 + n^3 = 7^3 + n^3 = (7 + n)(49 - 7n + n^2)\)
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\(8x^3 - 1 = (2x)^3 - 1^3 = (2x - 1)(4x^2 + 2x + 1)\)
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\(1 + 1000y^3 = 1^3 + (10y)^3 = (1 + 10y)(1 - 10y + 100y^2)\)
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\(16a^6 - 27c^3 = (2a^2)^3 - (3c)^3 = (2a^2 - 3c)(4a^4 + 6a^2c + 9c^2)\)
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\(343b^3 + 8d^3 = (7b)^3 + (2d)^3 = (7b + 2d)(49b^2 - 14bd + 4d^2)\)
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\(64x^6 - 125m^3 = (4x^2)^3 - (5m)^3 = (4x^2 - 5m)(16x^4 + 20x^2m + 25m^2)\)
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\(729n^{12} + 1 = (9n^4)^3 + 1^3 = (9n^4 + 1)(81n^8 - 9n^4 + 1)\)
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\(8y^3 + 512z^9 = (2y)^3 + (8z^3)^3 = (2y + 8z^3)(4y^2 - 16yz^3 + 64z^6)\)
Ответ:
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\((x + y)(x^2 - xy + y^2)\)
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\((m - n)(m^2 + mn + n^2)\)
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\((a + 2)(a^2 - 2a + 4)\)
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\((b - 3)(b^2 + 3b + 9)\)
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\((4 + c)(16 - 4c + c^2)\)
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\((5 - d)(25 + 5d + d^2)\)
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\((m + 6)(m^2 - 6m + 36)\)
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\((7 + n)(49 - 7n + n^2)\)
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\((2x - 1)(4x^2 + 2x + 1)\)
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\((1 + 10y)(1 - 10y + 100y^2)\)
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\((2a^2 - 3c)(4a^4 + 6a^2c + 9c^2)\)
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\((7b + 2d)(49b^2 - 14bd + 4d^2)\)
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\((4x^2 - 5m)(16x^4 + 20x^2m + 25m^2)\)
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\((9n^4 + 1)(81n^8 - 9n^4 + 1)\)
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\((2y + 8z^3)(4y^2 - 16yz^3 + 64z^6)\)