Краткое пояснение: Здесь применяем формулы суммы и разности кубов: \((a + b)(a^2 - ab + b^2) = a^3 + b^3\) и \((a - b)(a^2 + ab + b^2) = a^3 - b^3\).
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\((p + q)(p^2 - pq + q^2) = p^3 + q^3\)
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\((k - m)(k^2 + km + m^2) = k^3 - m^3\)
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\((a + 8)(a^2 - 8a + 64) = a^3 + 8^3 = a^3 + 512\)
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\((8 - b)(64 + 8b + b^2) = 8^3 - b^3 = 512 - b^3\)
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\((c + 6)(c^2 - 6c + 36) = c^3 + 6^3 = c^3 + 216\)
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\((7 - d)(49 + 7d + d^2) = 7^3 - d^3 = 343 - d^3\)
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\((2 + k)(4 - 2k + k^2) = (2 + k)(2^2 - 2k + k^2) = 2^3 + k^3 = 8 + k^3\)
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\((l - 1)(l^2 + l + 1) = l^3 - 1\)
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\((m^2 + n)(m^4 - m^2n + n^2) = (m^2)^3 + n^3 = m^6 + n^3\)
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\((x - y^3)(x^2 + xy^3 + y^6) = x^3 - (y^3)^3 = x^3 - y^9\)
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\((8a^2 + b^2)(64a^4 - 8a^2b^2 + b^4) = (8a^2)^3 + (b^2)^3 = 512a^6 + b^6\)
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\((2c^3 - 3p^2)(4c^6 + 6c^3p^2 + 9p^4) = (2c^3)^3 - (3p^2)^3 = 8c^9 - 27p^6\)
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\((4p^6 + 3q^3)(16p^{12} - 12p^6q^3 + 27q^6) = (4p^6)^3 + (3q^3)^3 = 64p^{18} + 27q^9\)
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\((5x^2 - 6m^3)(25x^4 + 30x^2m^3 + 36m^6) = (5x^2)^3 - (6m^3)^3 = 125x^6 - 216m^9\)
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\((7d^5 + 1)(49d^{10} - 7d^5 + 1) = (7d^5)^3 + 1^3 = 343d^{15} + 1\)
Ответ:
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\(p^3 + q^3\)
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\(k^3 - m^3\)
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\(a^3 + 512\)
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\(512 - b^3\)
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\(c^3 + 216\)
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\(343 - d^3\)
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\(8 + k^3\)
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\(l^3 - 1\)
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\(m^6 + n^3\)
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\(x^3 - y^9\)
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\(512a^6 + b^6\)
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\(8c^9 - 27p^6\)
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\(64p^{18} + 27q^9\)
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\(125x^6 - 216m^9\)
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\(343d^{15} + 1\)