Краткое пояснение: Здесь применяем формулу разности квадратов: \((a - b)(a + b) = a^2 - b^2\).
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\((b - c)(b + c) = b^2 - c^2\)
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\((k + m)(k - m) = k^2 - m^2\)
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\((c - 1)(c + 1) = c^2 - 1\)
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\((2 + k)(2 - k) = 4 - k^2\)
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\((6 - a)(a + 6) = (6-a)(6+a) = 36 - a^2\)
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\((x + 144a)(x - 144a) = x^2 - (144a)^2 = x^2 - 20736a^2\)
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\((5m - 3k)(3k + 5m) = (5m - 3k)(5m + 3k) = 25m^2 - 9k^2\)
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\((12v - 11u)(11u + 12v) = (12v - 11u)(12v + 11u) = 144v^2 - 121u^2\)
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\((9p + n^2)(n^2 - 9p) = (n^2 + 9p)(n^2 - 9p) = n^4 - 81p^2\)
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\((15a^3 - 2b^2)(15a^3 + 2b^2) = 225a^6 - 4b^4\)
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\((6h^2 - 17m^4)(6h^2 + 17m^4) = 36h^4 - 289m^8\)
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\((11x^2 - 7z^3)(11x^2 + 7z^3) = 121x^4 - 49z^6\)
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\((8u^6 - 5b^2)(8u^6 + 5b^2) = 64u^{12} - 25b^4\)
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\((13a^7 - 18v^3)(13a^7 + 18v^3) = 169a^{14} - 324v^6\)
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\((20p^{10} - 19k^3)(20p^{10} + 19k^3) = 400p^{20} - 361k^6\)
Ответ:
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\(b^2 - c^2\)
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\(k^2 - m^2\)
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\(c^2 - 1\)
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\(4 - k^2\)
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\(36 - a^2\)
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\(x^2 - 20736a^2\)
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\(25m^2 - 9k^2\)
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\(144v^2 - 121u^2\)
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\(n^4 - 81p^2\)
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\(225a^6 - 4b^4\)
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\(36h^4 - 289m^8\)
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\(121x^4 - 49z^6\)
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\(64u^{12} - 25b^4\)
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\(169a^{14} - 324v^6\)
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\(400p^{20} - 361k^6\)