$$ \frac{3}{\sqrt[3]{5}} = \frac{3 \cdot \sqrt[3]{5^2}}{\sqrt[3]{5} \cdot \sqrt[3]{5^2}} = \frac{3\sqrt[3]{25}}{5} $$
$$ \frac{6}{\sqrt{7}-2} = \frac{6(\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} = \frac{6(\sqrt{7}+2)}{7-4} = \frac{6(\sqrt{7}+2)}{3} = 2(\sqrt{7}+2) = 2\sqrt{7}+4 $$