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МатематикаВопрос:
5. (log2(4)) * (log3(81))
Ответ:
log2(4) = log2(2^2) = 2 * log2(2) = 2 * 1 = 2
log3(81) = log3(3^4) = 4 * log3(3) = 4 * 1 = 4
(log2(4)) * (log3(81)) = 2 * 4 = 8
Ответ: 8
log3(81) = log3(3^4) = 4 * log3(3) = 4 * 1 = 4
(log2(4)) * (log3(81)) = 2 * 4 = 8
Ответ: 8
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