269 2) (m-5) (m-1)-(m+2) (m-3) при т=-2 3/5;

2) $$(m-5)(m-1) - (m+2)(m-3) = m^2 - m - 5m + 5 - (m^2 - 3m + 2m - 6) = m^2 - 6m + 5 - m^2 + m + 6 = -5m + 11$$.

При $$m = -2\frac{3}{5} = -\frac{13}{5}$$, получим $$ -5 \cdot (-\frac{13}{5}) + 11 = 13 + 11 = 24 $$.

Ответ: 24