Найдите корень уравнения 10/(6-x)=4/(x+2).

\[\frac{10}{6 - x} = \frac{4}{x + 2}\]

\[10 \cdot (x + 2) = 4 \cdot (6 - x)\]

\[10x + 20 = 24 - 4x\]

\[10x + 4x = 24 - 20\]

\[14x = 4\]

\[x = \frac{4}{14}\]

\[x = \frac{2}{7}.\]