a) $$13\frac{8}{9}-4 = 9\frac{8}{9}$$
б) $$17\frac{5}{14}-5\frac{3}{14} = (17-5)+(\frac{5}{14}-\frac{3}{14}) = 12 + \frac{2}{14} = 12\frac{1}{7}$$
в) $$9\frac{5}{7}-3\frac{6}{7} = (9-3)+(\frac{5}{7}-\frac{6}{7}) = 6 - \frac{1}{7} = 5\frac{7}{7} - \frac{1}{7} = 5\frac{6}{7}$$
г) $$100-20\frac{3}{5} = 99\frac{5}{5}-20\frac{3}{5} = (99-20) + (\frac{5}{5}-\frac{3}{5}) = 79 + \frac{2}{5} = 79\frac{2}{5}$$
Ответ: a) $$9\frac{8}{9}$$; б) $$12\frac{1}{7}$$; в) $$5\frac{6}{7}$$; г) $$79\frac{2}{5}$$