Найдите решение системы уравнений: x-y=1; y-z=2; z-x=-3.

\[\left\{ \begin{matrix}
x - y = 1\ \ \ \\
y - z = 2\ \ \ \\
z - x = - 3 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
z = x - 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x - 1 - (x - 3) = 2 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
z = x - 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x - 1 - x + 3 = 2\ \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
y = x - 1 \\
z = x - 3 \\
2 = 2\ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
z = x - 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x - любое\ число \\
\end{matrix} \right.\ \]

\[Ответ:(x;x - 1;x - 3).\]