Сумма углов треугольника равна 180 градусов.
\[51^{\circ} + 89^{\circ} + (6r + 2)^{\circ} = 180^{\circ}\]
\[140 + 6r + 2 = 180\]
\[6r + 142 = 180\]
\[6r = 180 - 142\]
\[6r = 38\]
\[r = \frac{38}{6} = \frac{19}{3} = 6\frac{1}{3}\]
Ответ: \[r = 6\frac{1}{3}\]