3. Найдите значение выражения $$rac{x-6y^2}{2y} + 3y$$ при $$x=-8$$, $$y=0.1$$

$$\frac{x-6y^2}{2y} + 3y = \frac{-8-6(0.1)^2}{2(0.1)} + 3(0.1) = \frac{-8-6(0.01)}{0.2} + 0.3 = \frac{-8-0.06}{0.2} + 0.3 = \frac{-8.06}{0.2} + 0.3 = -40.3 + 0.3 = -40$$ Ответ: -40