342. Найдите значение выражения: 1) $$15\frac{4}{9} - 4\frac{4}{9} \cdot 3\frac{3}{8}$$; 2) $$\frac{81}{88} \cdot (6-1\frac{13}{15} \cdot 1\frac{19}{21})$$; 3) $$(5\frac{1}{16} - 1\frac{1}{8}) \cdot (\frac{5}{6} + \frac{3}{14})$$; 4) $$5\frac{1}{16} - 1\frac{1}{8} \cdot (\frac{5}{6} + \frac{3}{14})$$

1) $$15\frac{4}{9} - 4\frac{4}{9} \cdot 3\frac{3}{8} = \frac{139}{9} - \frac{40}{9} \cdot \frac{27}{8} = \frac{139}{9} - \frac{40 \cdot 27}{9 \cdot 8} = \frac{139}{9} - \frac{5 \cdot 3}{1 \cdot 1} = \frac{139}{9} - 15 = \frac{139}{9} - \frac{15 \cdot 9}{1 \cdot 9} = \frac{139}{9} - \frac{135}{9} = \frac{139-135}{9} = \frac{4}{9}$$

Ответ: $$\frac{4}{9}$$

2) $$\frac{81}{88} \cdot (6-1\frac{13}{15} \cdot 1\frac{19}{21}) = \frac{81}{88} \cdot (6 - \frac{28}{15} \cdot \frac{40}{21}) = \frac{81}{88} \cdot (6 - \frac{28 \cdot 40}{15 \cdot 21}) = \frac{81}{88} \cdot (6 - \frac{4 \cdot 8}{3 \cdot 3}) = \frac{81}{88} \cdot (6 - \frac{32}{9}) = \frac{81}{88} \cdot (\frac{6 \cdot 9}{1 \cdot 9} - \frac{32}{9}) = \frac{81}{88} \cdot (\frac{54}{9} - \frac{32}{9}) = \frac{81}{88} \cdot \frac{54-32}{9} = \frac{81}{88} \cdot \frac{22}{9} = \frac{81 \cdot 22}{88 \cdot 9} = \frac{9 \cdot 1}{4 \cdot 1} = \frac{9}{4} = 2\frac{1}{4}$$

Ответ: $$2\frac{1}{4}$$

3) $$(5\frac{1}{16} - 1\frac{1}{8}) \cdot (\frac{5}{6} + \frac{3}{14}) = (\frac{81}{16} - \frac{9}{8}) \cdot (\frac{5}{6} + \frac{3}{14}) = (\frac{81}{16} - \frac{9 \cdot 2}{8 \cdot 2}) \cdot (\frac{5 \cdot 7}{6 \cdot 7} + \frac{3 \cdot 3}{14 \cdot 3}) = (\frac{81}{16} - \frac{18}{16}) \cdot (\frac{35}{42} + \frac{9}{42}) = \frac{81-18}{16} \cdot \frac{35+9}{42} = \frac{63}{16} \cdot \frac{44}{42} = \frac{63 \cdot 44}{16 \cdot 42} = \frac{9 \cdot 11}{4 \cdot 6} = \frac{99}{24} = \frac{33}{8} = 4\frac{1}{8}$$

Ответ: $$4\frac{1}{8}$$

4) $$5\frac{1}{16} - 1\frac{1}{8} \cdot (\frac{5}{6} + \frac{3}{14}) = \frac{81}{16} - \frac{9}{8} \cdot (\frac{5}{6} + \frac{3}{14}) = \frac{81}{16} - \frac{9}{8} \cdot (\frac{5 \cdot 7}{6 \cdot 7} + \frac{3 \cdot 3}{14 \cdot 3}) = \frac{81}{16} - \frac{9}{8} \cdot (\frac{35}{42} + \frac{9}{42}) = \frac{81}{16} - \frac{9}{8} \cdot \frac{35+9}{42} = \frac{81}{16} - \frac{9}{8} \cdot \frac{44}{42} = \frac{81}{16} - \frac{9 \cdot 44}{8 \cdot 42} = \frac{81}{16} - \frac{3 \cdot 11}{4 \cdot 7} = \frac{81}{16} - \frac{33}{28} = \frac{81 \cdot 7}{16 \cdot 7} - \frac{33 \cdot 4}{28 \cdot 4} = \frac{567}{112} - \frac{132}{112} = \frac{567-132}{112} = \frac{435}{112} = 3\frac{99}{112}$$

Ответ: $$3\frac{99}{112}$$