341. Найдите значение выражения: 1) $$(\frac{11}{18} - \frac{4}{9}) \cdot \frac{3}{16}$$; 2) $$\frac{11}{18} - \frac{4}{9} \cdot \frac{3}{16}$$; 3) $$1\frac{3}{5} \cdot (\frac{3}{4} + 1\frac{3}{8})$$; 4) $$1\frac{3}{5} \cdot \frac{3}{4} + 1\frac{3}{8}$$; 5) $$13\frac{4}{5} - 3\frac{1}{5} \cdot 3\frac{3}{4}$$; 6) $$1\frac{3}{25} \cdot 2\frac{1}{7} - 2\frac{1}{9} \cdot \frac{27}{190}$$; 7) $$4\frac{7}{12} \cdot 1\frac{3}{11} + 1\frac{1}{15} \cdot \frac{45}{64}$$; 8) $$(8 - 2\frac{1}{7} \cdot 3\frac{3}{9}) \cdot \frac{27}{44}$$; 9) $$(\frac{4}{5} + \frac{4}{7}) \cdot (7\frac{11}{12} - 5\frac{7}{9})$$; 10) $$\frac{4}{5} + \frac{4}{7} \cdot (7\frac{11}{12} - 5\frac{7}{9})$$

1) $$(\frac{11}{18} - \frac{4}{9}) \cdot \frac{3}{16} = (\frac{11}{18} - \frac{4 \cdot 2}{9 \cdot 2}) \cdot \frac{3}{16} = (\frac{11}{18} - \frac{8}{18}) \cdot \frac{3}{16} = \frac{11-8}{18} \cdot \frac{3}{16} = \frac{3}{18} \cdot \frac{3}{16} = \frac{1}{6} \cdot \frac{3}{16} = \frac{1 \cdot 3}{6 \cdot 16} = \frac{1 \cdot 1}{2 \cdot 16} = \frac{1}{32}$$

Ответ: $$\frac{1}{32}$$

2) $$\frac{11}{18} - \frac{4}{9} \cdot \frac{3}{16} = \frac{11}{18} - \frac{4 \cdot 3}{9 \cdot 16} = \frac{11}{18} - \frac{1 \cdot 1}{3 \cdot 4} = \frac{11}{18} - \frac{1}{12} = \frac{11 \cdot 2}{18 \cdot 2} - \frac{1 \cdot 3}{12 \cdot 3} = \frac{22}{36} - \frac{3}{36} = \frac{22-3}{36} = \frac{19}{36}$$

Ответ: $$\frac{19}{36}$$

3) $$1\frac{3}{5} \cdot (\frac{3}{4} + 1\frac{3}{8}) = \frac{8}{5} \cdot (\frac{3}{4} + \frac{11}{8}) = \frac{8}{5} \cdot (\frac{3 \cdot 2}{4 \cdot 2} + \frac{11}{8}) = \frac{8}{5} \cdot (\frac{6}{8} + \frac{11}{8}) = \frac{8}{5} \cdot \frac{6+11}{8} = \frac{8}{5} \cdot \frac{17}{8} = \frac{8 \cdot 17}{5 \cdot 8} = \frac{1 \cdot 17}{5 \cdot 1} = \frac{17}{5} = 3\frac{2}{5}$$

Ответ: $$3\frac{2}{5}$$

4) $$1\frac{3}{5} \cdot \frac{3}{4} + 1\frac{3}{8} = \frac{8}{5} \cdot \frac{3}{4} + \frac{11}{8} = \frac{8 \cdot 3}{5 \cdot 4} + \frac{11}{8} = \frac{2 \cdot 3}{5 \cdot 1} + \frac{11}{8} = \frac{6}{5} + \frac{11}{8} = \frac{6 \cdot 8}{5 \cdot 8} + \frac{11 \cdot 5}{8 \cdot 5} = \frac{48}{40} + \frac{55}{40} = \frac{48+55}{40} = \frac{103}{40} = 2\frac{23}{40}$$

Ответ: $$2\frac{23}{40}$$

5) $$13\frac{4}{5} - 3\frac{1}{5} \cdot 3\frac{3}{4} = \frac{69}{5} - \frac{16}{5} \cdot \frac{15}{4} = \frac{69}{5} - \frac{16 \cdot 15}{5 \cdot 4} = \frac{69}{5} - \frac{4 \cdot 3}{1 \cdot 1} = \frac{69}{5} - 12 = \frac{69}{5} - \frac{12 \cdot 5}{1 \cdot 5} = \frac{69}{5} - \frac{60}{5} = \frac{69-60}{5} = \frac{9}{5} = 1\frac{4}{5}$$

Ответ: $$1\frac{4}{5}$$

6) $$1\frac{3}{25} \cdot 2\frac{1}{7} - 2\frac{1}{9} \cdot \frac{27}{190} = \frac{28}{25} \cdot \frac{15}{7} - \frac{19}{9} \cdot \frac{27}{190} = \frac{28 \cdot 15}{25 \cdot 7} - \frac{19 \cdot 27}{9 \cdot 190} = \frac{4 \cdot 3}{5 \cdot 1} - \frac{1 \cdot 3}{1 \cdot 10} = \frac{12}{5} - \frac{3}{10} = \frac{12 \cdot 2}{5 \cdot 2} - \frac{3}{10} = \frac{24}{10} - \frac{3}{10} = \frac{24-3}{10} = \frac{21}{10} = 2\frac{1}{10}$$

Ответ: $$2\frac{1}{10}$$

7) $$4\frac{7}{12} \cdot 1\frac{3}{11} + 1\frac{1}{15} \cdot \frac{45}{64} = \frac{55}{12} \cdot \frac{14}{11} + \frac{16}{15} \cdot \frac{45}{64} = \frac{55 \cdot 14}{12 \cdot 11} + \frac{16 \cdot 45}{15 \cdot 64} = \frac{5 \cdot 7}{6 \cdot 1} + \frac{1 \cdot 3}{1 \cdot 4} = \frac{35}{6} + \frac{3}{4} = \frac{35 \cdot 2}{6 \cdot 2} + \frac{3 \cdot 3}{4 \cdot 3} = \frac{70}{12} + \frac{9}{12} = \frac{70+9}{12} = \frac{79}{12} = 6\frac{7}{12}$$

Ответ: $$6\frac{7}{12}$$

8) $$(8 - 2\frac{1}{7} \cdot 3\frac{3}{9}) \cdot \frac{27}{44} = (8 - \frac{15}{7} \cdot \frac{30}{9}) \cdot \frac{27}{44} = (8 - \frac{15 \cdot 30}{7 \cdot 9}) \cdot \frac{27}{44} = (8 - \frac{5 \cdot 10}{7 \cdot 1}) \cdot \frac{27}{44} = (8 - \frac{50}{7}) \cdot \frac{27}{44} = (\frac{8 \cdot 7}{1 \cdot 7} - \frac{50}{7}) \cdot \frac{27}{44} = (\frac{56}{7} - \frac{50}{7}) \cdot \frac{27}{44} = \frac{56-50}{7} \cdot \frac{27}{44} = \frac{6}{7} \cdot \frac{27}{44} = \frac{6 \cdot 27}{7 \cdot 44} = \frac{3 \cdot 27}{7 \cdot 22} = \frac{81}{154}$$

Ответ: $$\frac{81}{154}$$

9) $$(\frac{4}{5} + \frac{4}{7}) \cdot (7\frac{11}{12} - 5\frac{7}{9}) = (\frac{4 \cdot 7}{5 \cdot 7} + \frac{4 \cdot 5}{7 \cdot 5}) \cdot (\frac{95}{12} - \frac{52}{9}) = (\frac{28}{35} + \frac{20}{35}) \cdot (\frac{95 \cdot 3}{12 \cdot 3} - \frac{52 \cdot 4}{9 \cdot 4}) = \frac{28+20}{35} \cdot (\frac{285}{36} - \frac{208}{36}) = \frac{48}{35} \cdot \frac{285-208}{36} = \frac{48}{35} \cdot \frac{77}{36} = \frac{48 \cdot 77}{35 \cdot 36} = \frac{4 \cdot 11}{5 \cdot 3} = \frac{44}{15} = 2\frac{14}{15}$$

Ответ: $$2\frac{14}{15}$$

10) $$\frac{4}{5} + \frac{4}{7} \cdot (7\frac{11}{12} - 5\frac{7}{9}) = \frac{4}{5} + \frac{4}{7} \cdot (\frac{95}{12} - \frac{52}{9}) = \frac{4}{5} + \frac{4}{7} \cdot (\frac{95 \cdot 3}{12 \cdot 3} - \frac{52 \cdot 4}{9 \cdot 4}) = \frac{4}{5} + \frac{4}{7} \cdot (\frac{285}{36} - \frac{208}{36}) = \frac{4}{5} + \frac{4}{7} \cdot \frac{285-208}{36} = \frac{4}{5} + \frac{4}{7} \cdot \frac{77}{36} = \frac{4}{5} + \frac{4 \cdot 77}{7 \cdot 36} = \frac{4}{5} + \frac{1 \cdot 11}{1 \cdot 9} = \frac{4}{5} + \frac{11}{9} = \frac{4 \cdot 9}{5 \cdot 9} + \frac{11 \cdot 5}{9 \cdot 5} = \frac{36}{45} + \frac{55}{45} = \frac{36+55}{45} = \frac{91}{45} = 2\frac{1}{45}$$

Ответ: $$2\frac{1}{45}$$