342. Найдите значение выражения:
- $$15\frac{4}{9} - 4\frac{4}{9} \cdot \frac{3}{8} = \frac{15\cdot9+4}{9} - \frac{4\cdot9+4}{9} \cdot \frac{3}{8} = \frac{139}{9} - \frac{40}{9} \cdot \frac{3}{8} = \frac{139}{9} - \frac{5}{3} = \frac{139}{9} - \frac{5\cdot3}{3\cdot3} = \frac{139}{9} - \frac{15}{9} = \frac{124}{9} = 13\frac{7}{9}$$
- $$(5\frac{1}{16} - 1\frac{1}{8})(\frac{5}{6} + \frac{3}{14}) = (\frac{5\cdot16+1}{16} - \frac{1\cdot8+1}{8})(\frac{5}{6} + \frac{3}{14}) = (\frac{81}{16} - \frac{9}{8})(\frac{5}{6} + \frac{3}{14}) = (\frac{81}{16} - \frac{9\cdot2}{8\cdot2})(\frac{5\cdot7}{6\cdot7} + \frac{3\cdot3}{14\cdot3}) = (\frac{81}{16} - \frac{18}{16})(\frac{35}{42} + \frac{9}{42}) = \frac{63}{16} \cdot \frac{44}{42} = \frac{9}{8} \cdot \frac{11}{3} = \frac{3}{8} \cdot \frac{11}{1} = \frac{33}{8} = 4\frac{1}{8}$$
Ответ: 1) $$13\frac{7}{9}$$; 3) $$4\frac{1}{8}$$