а)
$$\frac{3}{8} + \frac{1}{20} + \frac{7}{40} = \frac{3 \cdot 5}{8 \cdot 5} + \frac{1 \cdot 2}{20 \cdot 2} + \frac{7}{40} = \frac{15}{40} + \frac{2}{40} + \frac{7}{40} = \frac{15 + 2 + 7}{40} = \frac{24}{40} = \frac{3}{5}$$
Ответ: 3/5
б)
$$\frac{1}{6} + (\frac{3}{5} - \frac{1}{3}) = \frac{1}{6} + (\frac{3 \cdot 3}{5 \cdot 3} - \frac{1 \cdot 5}{3 \cdot 5}) = \frac{1}{6} + (\frac{9}{15} - \frac{5}{15}) = \frac{1}{6} + \frac{4}{15} = \frac{1 \cdot 5}{6 \cdot 5} + \frac{4 \cdot 2}{15 \cdot 2} = \frac{5}{30} + \frac{8}{30} = \frac{5 + 8}{30} = \frac{13}{30}$$
Ответ: 13/30
в)
$$\frac{8}{9} - (\frac{1}{10} + \frac{2}{5}) = \frac{8}{9} - (\frac{1}{10} + \frac{2 \cdot 2}{5 \cdot 2}) = \frac{8}{9} - (\frac{1}{10} + \frac{4}{10}) = \frac{8}{9} - \frac{5}{10} = \frac{8}{9} - \frac{1}{2} = \frac{8 \cdot 2}{9 \cdot 2} - \frac{1 \cdot 9}{2 \cdot 9} = \frac{16}{18} - \frac{9}{18} = \frac{16 - 9}{18} = \frac{7}{18}$$
Ответ: 7/18
г)
$$(\frac{5}{8} + \frac{1}{16}) - \frac{9}{16} = (\frac{5 \cdot 2}{8 \cdot 2} + \frac{1}{16}) - \frac{9}{16} = (\frac{10}{16} + \frac{1}{16}) - \frac{9}{16} = \frac{11}{16} - \frac{9}{16} = \frac{11 - 9}{16} = \frac{2}{16} = \frac{1}{8}$$
Ответ: 1/8