Найдите значение выражения: 7. $$\frac{2^{-7} \cdot 2^{-8}}{2^{-16}}$$ 8. $$\frac{9^{-5} \cdot 9^{-8}}{9^{-15}}$$ 9. $$\frac{3^{-4} \cdot 3^{-8}}{3^{-14}}$$ 10. $$\frac{7^{-3} \cdot 7^{-8}}{7^{-13}}$$ 11. $$\frac{11^{-5} \cdot 11^{-13}}{11^{-19}}$$ 12. $$\frac{5^{-3} \cdot 5^{-9}}{5^{-14}}$$ 13. $$\frac{1}{5^{-8} \cdot 5^6}$$ 14. $$\frac{1}{7^{-14} \cdot 7^{13}}$$ 15. $$\frac{1}{2^{-19} \cdot 2^{16}}$$ 16. $$\frac{1}{8^{-7} \cdot 8^6}$$ 17. $$\frac{1}{3^{-10} \cdot 3^8}$$ 18. $$\frac{1}{4^{-10} \cdot 4^9}$$

**Решение:**

7. $$\frac{2^{-7} \cdot 2^{-8}}{2^{-16}} = \frac{2^{-15}}{2^{-16}} = 2^{-15 - (-16)} = 2^{-15 + 16} = 2^1 = 2$$
8. $$\frac{9^{-5} \cdot 9^{-8}}{9^{-15}} = \frac{9^{-13}}{9^{-15}} = 9^{-13 - (-15)} = 9^{-13 + 15} = 9^2 = 81$$
9. $$\frac{3^{-4} \cdot 3^{-8}}{3^{-14}} = \frac{3^{-12}}{3^{-14}} = 3^{-12 - (-14)} = 3^{-12 + 14} = 3^2 = 9$$
10. $$\frac{7^{-3} \cdot 7^{-8}}{7^{-13}} = \frac{7^{-11}}{7^{-13}} = 7^{-11 - (-13)} = 7^{-11 + 13} = 7^2 = 49$$
11. $$\frac{11^{-5} \cdot 11^{-13}}{11^{-19}} = \frac{11^{-18}}{11^{-19}} = 11^{-18 - (-19)} = 11^{-18 + 19} = 11^1 = 11$$
12. $$\frac{5^{-3} \cdot 5^{-9}}{5^{-14}} = \frac{5^{-12}}{5^{-14}} = 5^{-12 - (-14)} = 5^{-12 + 14} = 5^2 = 25$$
13. $$\frac{1}{5^{-8} \cdot 5^6} = \frac{1}{5^{-2}} = 5^2 = 25$$
14. $$\frac{1}{7^{-14} \cdot 7^{13}} = \frac{1}{7^{-1}} = 7^1 = 7$$
15. $$\frac{1}{2^{-19} \cdot 2^{16}} = \frac{1}{2^{-3}} = 2^3 = 8$$
16. $$\frac{1}{8^{-7} \cdot 8^6} = \frac{1}{8^{-1}} = 8^1 = 8$$
17. $$\frac{1}{3^{-10} \cdot 3^8} = \frac{1}{3^{-2}} = 3^2 = 9$$
18. $$\frac{1}{4^{-10} \cdot 4^9} = \frac{1}{4^{-1}} = 4^1 = 4$$

**Ответ:**
7. 2
8. 81
9. 9
10. 49
11. 11
12. 25
13. 25
14. 7
15. 8
16. 8
17. 9
18. 4