(\( \frac{a^{-1}}{b^2} \))-2 \( \cdot \) (a3b5)-1 = \((\frac{b^2}{a^{-1}})\)^2 \( \cdot \) (\(\frac{1}{a^3b^5}\)) = (a \( \cdot \) b2)2 \( \cdot \) (\(\frac{1}{a^3b^5}\)) = a2b4 \( \cdot \) \(\frac{1}{a^3b^5}\) = \(\frac{1}{ab}\)
\(\frac{1}{ab}\) = \(\frac{1}{4 \cdot \frac{1}{2}}\) = \(\frac{1}{2}\)
Ответ: \(\frac{1}{2}\)