x-5 \( \cdot \) x8 = x-5+8 = x3
y2 : y-3 = y2-(-3) = y5
(a-2)3 = a-2\( \cdot \)3 = a-6 = \(\frac{1}{a^6}\)
(b-4c2)-2 = b-4\( \cdot \)(-2)c2\( \cdot \)(-2) = b8c-4 = \(\frac{b^8}{c^4}\)
\(\frac{m^{-3}n^4}{m^{-5}n^2}\) = m-3-(-5)n4-2 = m2n2
(2x-1y3)2 \( \cdot \) (x2y-2) = (4x-2y6) \( \cdot \) (x2y-2) = 4x-2+2y6-2 = 4y4
Ответ: 2.1: x3; 2.2: y5; 2.3: \(\frac{1}{a^6}\); 2.4: \(\frac{b^8}{c^4}\); 2.5: m2n2; 2.6: 4y4