Решение:
\[ \frac{3}{5} \div \frac{11}{40} = \frac{3}{5} \times \frac{40}{11} \]
\[ \frac{3}{5^1} \times \frac{40^8}{11} = \frac{3}{1} \times \frac{8}{11} \]
\[ \frac{3 \times 8}{1 \times 11} = \frac{24}{11} \]
\[ \frac{9}{11} + \frac{24}{11} \]
\[ \frac{9 + 24}{11} = \frac{33}{11} \]
\[ \frac{33}{11} = 3 \]
Ответ: 3