Решение задания 1

a) 4¹¹ × 4⁻⁹ = 4¹¹⁻⁹ = 4² = 16

б) 6⁻⁵ : 6⁻³ = 6⁻⁵⁻⁽⁻³⁾ = 6⁻⁵⁺³ = 6⁻² = $$\frac{1}{6^2}$$ = $$\frac{1}{36}$$

в) (2⁻²)³ = 2⁻²ᐧ³ = 2⁻⁶ = $$\frac{1}{2^6}$$ = $$\frac{1}{64}$$

Ответ:

• a) 16
• б) $$\frac{1}{36}$$
• в) $$\frac{1}{64}$$