5. Найти разность дробей: a)를 6) 3-2 B)5-3 7

a) $$\frac{7}{10} - \frac{1}{2} = \frac{7}{10} - \frac{1 \cdot 5}{2 \cdot 5} = \frac{7}{10} - \frac{5}{10} = \frac{7-5}{10} = \frac{2}{10} = \frac{1}{5}$$

б) $$3 \frac{1}{6} - 2 \frac{1}{12} = 3 \frac{1 \cdot 2}{6 \cdot 2} - 2 \frac{1}{12} = 3 \frac{2}{12} - 2 \frac{1}{12} = (3-2) + (\frac{2}{12} - \frac{1}{12}) = 1 + \frac{1}{12} = 1 \frac{1}{12}$$

в) $$5 \frac{1}{14} - 3 \frac{2}{7} = 5 \frac{1}{14} - 3 \frac{2 \cdot 2}{7 \cdot 2} = 5 \frac{1}{14} - 3 \frac{4}{14} = (5-3) + (\frac{1}{14} - \frac{4}{14}) = 2 - \frac{3}{14} = 1 + \frac{14}{14} - \frac{3}{14} = 1 \frac{11}{14}$$

Ответ: а) $$\frac{1}{5}$$, б) $$1 \frac{1}{12}$$, в) $$1 \frac{11}{14}$$