\[y = kx + b;\ \ \ A( - 3;26);\ \ B(5; - 22).\]
\[Подставим\ координаты\ точек\ в\ \]
\[уравнение\ прямой\ и\ запишем\]
\[систему:\]
\[\left\{ \begin{matrix}
- 3k + b = 26 \\
5k + b = - 22 \\
\end{matrix} \right.\ ( - )\]
\[- 8k = 48\]
\[k = - 6.\]
\[\left\{ \begin{matrix}
b = 26 + 3k \\
k = - 6\ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix}
k = - 6\ \ \ \ \ \ \ \ \ \ \\
b = 26 - 18 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix}
k = - 6 \\
b = 8\ \ \ \\
\end{matrix} \right.\ \]
\[Уравнение\ прямой:\]
\[y = - 6x + 8.\]