Решите систему неравенств (7-5x)/2<=-4; x^2-4x<0.

\[\left\{ \begin{matrix}
\frac{7 - 5x}{2} \leq - 4\ \ | \cdot 2 \\
x^{2} - 4x < 0\ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix}
7 - 5x \leq - 8 \\
x(x - 4) < 0 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
5x \geq 15\ \ \ \ \ \ \ \ \ \ \\
x(x - 4) < 0 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix}
x \geq 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x(x - 4) < 0 \\
\end{matrix} \right.\ \]

\[Ответ:\ x \in \lbrack 3;4).\]