Решите систему уравнений: 1/3*(x-y)=4; 1/4*(x+y)=2.

\[\left\{ \begin{matrix}
\frac{1}{3} \cdot (x - y) = 4\ \ | \cdot 3 \\
\frac{1}{4} \cdot (x + y) = 2\ \ | \cdot 4 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
x - y = 12 \\
x + y = 8\ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
x = y + 12\ \ \ \ \ \ \ \\
y + 12 + y = 8 \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
x = y + 12 \\
2y = - 4\ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = - 2\ \ \ \ \ \ \ \ \ \ \\
x = - 2 + 12 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = - 2 \\
x = 10\ \\
\end{matrix} \right.\ \]

\[Ответ:(10;\ - 2).\]