Решите систему уравнений: 9x+2y=16; 3x-5y=11.

\[\left\{ \begin{matrix}
9x + 2y = 16\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
3x - 5y = 11\ \ \ | \cdot ( - 3) \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
9x + 2y = 16\ \ \ \ \ \ \ \ \ \ \ \ (1) \\
- 9x + 15y = - 33\ \ \ (2) \\
\end{matrix} \right.\ \]

\[(1) + (2) \Longrightarrow 17y = - 17\]

\[\left\{ \begin{matrix}
17y = - 17\ \ \ \ \ \\
9x + 2y = 16 \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = - 1\ \ \ \ \ \ \ \ \ \ \ \ \\
9x = 16 - 2y \\
\end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\left\{ \begin{matrix}
y = - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
x = \frac{16}{9} - \frac{2}{9} \cdot ( - 1) \\
\end{matrix} \right.\ \text{\ \ \ \ }\]

\[\left\{ \begin{matrix}
y = - 1 \\
x = 2\ \ \ \\
\end{matrix} \right.\ \]

\[Ответ:(2; - 1).\]