Решите уравнение: |2x-4y-10|+(3x+y-1)^2=0.

\[\left\{ \begin{matrix}
2x - 4y - 10 = 0 \\
3x + y - 1 = 0\ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
2x - 4y - 10 = 0 \\
y = 1 - 3x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
2x - 4(1 - 3x) - 10 = 0 \\
y = 1 - 3x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \]

\[\left\{ \begin{matrix}
2x - 4 + 12x - 10 = 0 \\
y = 1 - 3x\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
14x = 14\ \ \ \\
y = 1 - 3x \\
\end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix}
x = 1\ \ \ \\
y = - 2 \\
\end{matrix} \right.\ \]

\[Ответ:(1; - 2).\]