Решите уравнение: (2x-1)(2x+1)=2(x-3)^2+x(2x-3).

\[(2x - 1)(2x + 1) =\]

\[= 2(x - 3)^{2} + x(2x - 3)\]

\[4x^{2} - 1 =\]

\[= 2x^{2} - 12x + 18 + 2x^{2} - 3x\]

\[4x^{2} - 2x^{2} + 12x - 2x^{2} + 3x =\]

\[= 18 + 1\]

\[15x = 19\]

\[x = \frac{19}{15}\]

\[Ответ:x = 1\frac{4}{15}.\]